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題 名 | Hydraulic Conductivity Identification of Groundwater Sandbox Model=地下水砂箱模型水力傳導係數推求 |
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作 者 | 葉一隆; 陳庭堅; 王裕民; | 書刊名 | 國立屏東科技大學學報 |
卷 期 | 9:2 2000.06[民89.06] |
頁 次 | 頁133-142 |
分類號 | 443.67 |
關鍵詞 | 水力傳導係數; 砂箱模型; 積分有限差分法; Hydraulic conductivity; Sandbox model; Integrated finite difference method; |
語 文 | 英文(English) |
中文摘要 | 地下水流或溶質傳輸之現地問題相當複雜,而且現地試驗的費用昂貴,而砂箱模型為一常用來模擬地下水流或溶質傳輸的替代方法。 本文利用三種方法來推求砂箱棤型之水力傳導係數,第一種為定水頭試驗,由試驗結果得知最高的水力傳導係數0.78cm/min,第三種方法為利用數值模擬後,再利迴歸分析方法求得地下水水位誤差最小之水力傳導係數為1.14cm/min。在此分析方法中,Neuman法因砂箱四週邊界之限制而非徑向流,因此會產生低估之結果。在利用數值模擬來推求水力導係數時,利用定水頭試驗結果為上限值,而以Neuman法求得結果為下限值;利用數值模式模擬不同水力傳導係數時之洩降值,並與抽水試驗於抽水十分鐘時之洩降值比較,並將其誤差值平均後套配出一二次方程式,而求其對水力傳導係數之一階導函數值為零,由所得結果可知在砂箱模型之水力傳導係數推求以數值法來求得為可行之方法。 |
英文摘要 | Field problems in groundwater flow or solute transport are complex. It is difficult to develop field experiments which are expensive. The sandbox model is an alternative method that simulates the groundwater flow or solute transport problems in porous media. The hydraulic conductivity of the sandbox was determined by three methods: (1)The constant head test generated the highest hydraulic conductivity (1.44 cm/min). (2)the Neuman interpretation method based on an analytical model of radial flow produced the lowest hydraulic conductivity (0.78 cm/min). (3)The numerical fitting method resulted in a hydraulic conductivity of 1.14 cm/min. In tests, because the boundaries were finite and constrained by the sidewalls of the tank, the huydraulic conductivity obtained by the Neuman interpretation method could be underestimated. Therefore, hydraulic conductivity was set at its lowest for the numerical simulations. The third method was based on the comparison of numerically calculated drawdown values with observation data at three locations after ten minutes of pumping. A second order equation was fitted through the average deviations for different hydraulic conductivity values. The minimum of this second order equation determined the result of the third method. |
本系統中英文摘要資訊取自各篇刊載內容。